Question

Tĩm x,y biết

a)\(\frac{x+5}{-3}=\frac{-x+2}{4}\)

b)\(\frac{x-1}{6}=\frac{2}{y+3}\)

c)\(\frac{2}{x+3}=\frac{2-y}{5}\)

Answer 1

a) ta có : 4(x+5) = -3(-x+2) 

=> 4x + 20 = 3x - 6

=>4x - 3x = - 6 - 20

=> x = -26

Answer 2

a)\(\Leftrightarrow\frac{x+5}{-3}=\frac{-x+5}{3}\)

\(\Leftrightarrow\frac{-x+2}{4}=\frac{-x-2}{4}\)

\(\Rightarrow\frac{-x+5}{3}=\frac{-x-2}{4}\)

\(\Leftrightarrow\frac{-x}{3}-\frac{5}{3}=\frac{1}{2}-\frac{x}{4}\)

\(\Rightarrow\frac{-x}{12}-\frac{13}{6}=0\)

\(\Leftrightarrow\frac{x+26}{12}=0\)

=>x+26=0

=>x=-26

phần b,c tự làm tiếp