Question

Tìm x,y ; biết:

(2x+6)²+5.(y-3)²⁰< hoặc = 0

Answer 1

Ta có:\(\left(2x+6\right)^2\ge0\)

\(5\left(y-3\right)^{20}\ge0\)

\(\Rightarrow\left(2x+6\right)^2+5\left(y-3\right)^{20}\ge0\)

Mà \(\left(2x+6\right)^2+5\left(y-3\right)^{20}\le0\)

\(\Rightarrow\left(2x+6\right)^2+5\left(y-3\right)^{20}=0\\ \Rightarrow\left\{{}\begin{matrix}\left(2x+6\right)^2=0\\5\left(y-3\right)^2=0\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}2x+6=0\\y-3=0\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}x=-3\\y=3\end{matrix}\right.\)