Đặt \(\dfrac{x}{2}=\dfrac{y}{4}=k\Rightarrow x=2k,y=4k\)
\(\Rightarrow2k.4k=280\)
\(\Rightarrow8k^2=280\Rightarrow k^2=35\Rightarrow k=\pm\sqrt{35}\)
\(\Rightarrow\left\{{}\begin{matrix}x=2k=\pm\sqrt{70}\\y=4k=\pm\sqrt{140}\end{matrix}\right.\)
Mà \(x,y\) cùng dấu
Vậy...