\(2\left|x+6\right|-\left|x-6\right|=0\)
\(\Rightarrow\left|x+6\right|-\left|x-6\right|=0\)
\(\left|x+6\right|,\left|x-6\right|\ge0\)
\(\Rightarrow\orbr{\begin{cases}x+6=0\\x-6=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-6\\x=6\end{cases}}\)
\(2\left|x+6\right|-\left|x-6\right|=0\)
Ta có \(2\left|x+6\right|\ge0\forall x;\left|x-6\right|\ge0\forall x\)
\(\Rightarrow2\left|x+6\right|-\left|x-6\right|\ge0\forall x\)
\(\Rightarrow2\left|x+6\right|-\left|x-6\right|=0\)
\(\Rightarrow\orbr{\begin{cases}2\left(x+6\right)=0\\x-6=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-6\\x=6\end{cases}}\)
P/s: chưa chắc :v