\(\left|x+5\right|-2x=1\)
TH1: \(\left(x+5\right)-2x=1\left(x\ge-5\right)\)
\(\Leftrightarrow x+5-2x=1\)
\(\Leftrightarrow5-x=1\)
\(\Leftrightarrow x=5-1\)
\(\Leftrightarrow x=4\left(tm\right)\)
TH2: \(-\left(x+5\right)-2x=1\left(x< -5\right)\)
\(\Leftrightarrow-x-5-2x=1\)
\(\Leftrightarrow-5-3x=1\)
\(\Leftrightarrow3x=-5-1\)
\(\Leftrightarrow3x=-6\)
\(\Leftrightarrow x=\dfrac{-6}{3}\)
\(\Leftrightarrow x=-2\) (ktm)
Vậy: x = 4