\(\Leftrightarrow\left(\dfrac{x+1}{2021}+1\right)+\left(\dfrac{x+2}{2020}+1\right)=\left(\dfrac{x+3}{2019}+1\right)+\left(\dfrac{x+4}{2018}+1\right)\)
=>x+2022=0
=>x=-2022
\(\Leftrightarrow\left(\dfrac{x+1}{2021}+1\right)+\left(\dfrac{x+2}{2020}+1\right)=\left(\dfrac{x+3}{2019}+1\right)+\left(\dfrac{x+4}{2018}+1\right)\)
=>x+2022=0
=>x=-2022
x+4/2018+x+3/2019=x+2/2020+x+1/2021
1 tìm x biết
x-4/2021+x-3/2020=x-2/2019+x-1/2018
giúp mk vs lm ơn
TÌM X BIẾT:
\(\frac{x-4}{2021}+\frac{x-3}{2020}=\frac{x-2}{2019}+\frac{x-1}{2018}\)
HELP ME!!
Ai nhanh và đúng mik tick.
tìm x biết:
(x+1)/2018+(x+1)/2019+(x+1)/2020+(x+1)/2021
Giúp mk nhanh vs nhé các bn
Tìm x biết:
( 1/2 + 1/3 + ... + 1/2021 ).x = 2021/1 +2019/2 + ... + 2/2019 + 1/2020
Tìm x biết:
( 1/2 + 1/3 + ... + 1/2021 ).x = 2021/1 +2019/2 + ... + 2/2019 + 1/2020
Cho x = 2020, tính giá trị:
P(x) = x^2021-2021x^2020+2021x^2019-2021x^2018+...+2021x-2020
Tìm X biết:
X+1/2020 + X+2/2019 +X+3/2018 +X+4/2017 =-4
tìm các số thực x,y thỏa mãn 2019.|x-1|+2020.|y-2|+2021.|y-3|+2022.|y-4|=4042
Tìm x biết
\(\frac{x+4}{2019}+\frac{x+3}{2020}=\frac{x+2}{2021}+\frac{x+1}{2022}\)