Question

tìm x

\(\sqrt{x-5}=9\)

\(3.\sqrt{2x}+\sqrt{8x}-2\sqrt{18x}=-4\)

\(\sqrt{2}.x^2-\sqrt{98}=0\)

\(\sqrt{x^2-2x+1}=5\)

\(\sqrt{17-4\sqrt{9+4\sqrt{5}}=0}\)

giúp tui vs mai tui nộp r

Answer 1

a: =>x-5=81

=>x=86

b: \(\Leftrightarrow3\sqrt{2x}+2\sqrt{2x}-6\sqrt{2x}=-4\)

=>-căn 2x=-4

=>2x=16

=>x=8

c: =>x²=7

=>x=căn 7 hoặc x=- căn 7

Answer 2

\(\sqrt{\left(x-1\right)^2}=5\Leftrightarrow\left|x-1\right|=5\Leftrightarrow x=6;x=-4\)