\(\left(2x-1\right)^2-\left(2-x\right)\left(2x-1\right)=0\)
\(4x^2-4x+1-5x+2x^2+2=0\)
\(6x^2-9x+3=0\)
\(6x^2-6x-3x+3=0\)
\(\left(x-1\right)\left(6x-3\right)=0\)
\(\hept{\begin{cases}x-1=0\\6x-3=0\end{cases}\Rightarrow\hept{\begin{cases}x=1\\x=\frac{1}{2}\end{cases}}}\)
Từ biểu thức, suy ra:
(2x-1)(2x-1-2+x)=0
<=>(2x-1)(3x-3)=0
<=>\(\orbr{\begin{cases}x=\frac{1}{2}\\x=1\end{cases}}\)
Vậy x\(\in\){1/2;1}
BÀI 6 tìm x
1,\(2x\left(x-5\right)-\left(3x+2x^2\right)=0\) 2,\(x\left(5-2x\right)+2x\left(x-1\right)=13\)
3,\(2x^3\left(2x-3\right)-x^2\left(4x^2-6x+2\right)=0\) 4,\(5x\left(x-1\right)-\left(x+2\right)\left(5x-7\right)=6\)
5,\(6x^2-\left(2x-3\right)\left(3x+2\right)=1\) 6,\(2x\left(1-x\right)+5=9-2x^2\)
Tìm \(x\):
\(8\)) \(1-\left(x-6\right)=4\left(2-2x\right)\)
\(9\))\(\left(3x-2\right)\left(x+5\right)=0\)
\(10\))\(\left(x+3\right)\left(x^2+2\right)=0\)
\(11\))\(\left(5x-1\right)\left(x^2-9\right)=0\)
\(12\))\(x\left(x-3\right)+3\left(x-3\right)=0\)
\(13\))\(x\left(x-5\right)-4x+20=0\)
\(14\))\(x^2+4x-5=0\)
1) \(\left(3-x^2\right)+6-2x=0\)
2) \(5\left(2x-1\right)+7=4\left(2-x\right)+2\)
3) \(x^2-6x+4\left(x-6\right)=0\)
4) \(\left(x+1\right)\left(2x-3\right)=x\left(x+1\right)\)
Tìm x, biết:
a, \(2x^3-x^2+2x-1=\)0
b, \(2018x-1+2019x\left(1-2018x\right)=0\)
c,\(\left(x+2\right)^3-x^2\left(x-6\right)-4=0\)
d,\(6x^2-\left(2x-3\right)\left(3x+2\right)=1\)
e,\(\left(x+1\right)^3-\left(x-1\right)\left(x^2+x+1\right)-2=0\)
g,\(7x^2+2x=0\)
h,\(x\left(x+4\right)-x^2-6x=10\)
i,\(x\left(x-1\right)+2x-2=0\)
k,\(\left(3x-1\right)^2-\left(x+5\right)^2=0\)
l,\(x\left(2x-3\right)-2\left(3-2x\right)=0\)
Tìm x
a, \(9x^2-49=0\) b, \(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-1\right)-27=0\)
c, (x-1)(x+2)-x-2=0 d, \(x\left(3x+2\right)+\left(x+1\right)^2-\left(2x-5\right)\left(2x+5\right)=0\)
e, (4x+1)(x-2)-(2x-3)(2x+1)=7
BT9: Tìm x biết
\(9,\left(2x-5\right)^2-\left(x+1\right)^2=0\)
\(10,\left(x+3\right)^2-x^2=45\)
\(11,\left(5x-4\right)^2-49x^2=0\)
\(12,16\left(x-1\right)^2-25=0\)
1\()\)\((\)x-1\()\)\(\left(5x+3\right)\)\(=\)\(\left(3x-8\right)\)\(\left(x-1\right)\)
2/\(\left(2x-1\right)^2\)\(+\)\(\left(2-x\right)\)\(\left(2x-1\right)\)\(=\)0
Giải các phương trình sau:
1, \(\dfrac{x-1}{3}-x=\dfrac{2x-4}{4}\)
2, \(\left(x-2\right)\left(2x-1\right)=x^2-2x\)
3, \(3x^2-4x+1=0\)
4, \(\left|2x-4\right|=0\)
5, \(\left|3x+2\right|=4\)
6, \(\left|2x-5\right|=\left|-x+2\right|\)
*Giúp mình với mình đg cần gấp ạ T_T
Tìm x, biết :
a/ \(\dfrac{1}{3}x\left(x^2-4\right)=0\)
b/ \(x\left(x+5\right)=x+5\)
c/ \(x^3-\dfrac{1}{9}x=0\)
3)\(^2-\left(x+5\right)^2=0\)
e/ \(\left(x+2\right)^2-\left(x-2\right)\left(x+2\right)=0\)
f/ \(x\left(2x-3\right)-6+4x=0\)
g/ \(2\left(3x-2\right)^2-9x^2+4=0\)
h/ \(x^2\left(x+1\right)+2x\left(x+1\right)=0\)
i/ \(4x^2+9x+5=0\)
