Question

tìm x

I3x+6I-Ix+2I=7

Answer 1

Xét x<-2=>x+2<0=>Ix+2I=-x-2

              =>3x+6<3.(-2)+6=>3x+6<0=>I3x+6I=-3x-6

=>I3x+6I-Ix+2I=7

=>-3x-6+x+2=7

=>(-3x+x)-(6-2)=7

=>-2x-4=7

=>-2x=7+4

=>-2x=11

=>x=11:(-2)

=>x=-11/2

Xét x>_-2=>x+2>_0=>Ix+2I=x+2

                =>3x+6>_3.(-2)+6=>3x+6>_0=>I3x+6I=3x+6

=>I3x+6I-Ix+2I=7

=>3x+6+x+2=7

=>(3x+x)+(6+2)=7

=>4x+8=7

=>4x=7-8

=>4x=-1

=>x=-1/4

Vậy x=-11/2,-1/4