Question

Tìm x

\(\frac{3}{4}-\frac{1}{4}x=\frac{1}{3}x-1\)

Answer 1

\(\frac{3}{4}-\frac{1}{4}.x=\frac{1}{3}.x-1\)

=> \(\frac{3}{4}+1=\frac{1}{3}.x+\frac{1}{4}.x\)

=> \(\frac{7}{4}=x.\left(\frac{1}{3}+\frac{1}{4}\right)\)

=> \(\frac{7}{4}=x.\frac{7}{12}\)

=> \(x=\frac{7}{12}:\frac{7}{4}\)

=> \(x=\frac{7}{12}.\frac{4}{7}=\frac{1}{3}\)

Answer 2

x-1+1/3

nên 1/3 =x-1/3

x=1/3

Answer 3

\(\frac{3}{4}-\frac{1}{4}x=\frac{1}{3}x-1\)

\(\frac{3}{4}+1=\frac{1}{3}x+\frac{1}{4}x\)

\(\frac{7}{4}=\left(\frac{1}{3}+\frac{1}{4}\right)x\)

\(\frac{7}{12}x=\frac{7}{4}\)

\(x=\frac{7}{4}:\frac{7}{12}=3\)

Vay x=3