Question

Tìm x:

\(\dfrac{x-2}{11}+\dfrac{x-2}{12}+\dfrac{x-2}{13}=\dfrac{x-2}{14}+\dfrac{x-2}{15}\)

Answer 1

bó tay.com

Answer 2

phê quá

Answer 3

chịu thôi

Answer 4

Bài làm

Ta có: x-2/11 + x-2/12 + x-2/13 = x-2/14 + x-2/15

=> x-2/11 + x-2/12 + x-2/13 - x-2/14 - x-2/15 = 0

=> ( x - 2 )( 1/11+1/12+1/13-1/14-1/15 ) = 0

=> x - 2 = 0 : ( 1/11+1/12+1/13-1/14-1/15)

=> x - 2 = 0

=> x = 2

Vậy x = 2

Answer 5

Dễ mak!!

Ta có:

     \(\frac{x-2}{11}+\frac{x-2}{12}+\frac{x-2}{13}=\frac{x-2}{14}+\frac{x-2}{15}\) 

\(=>\frac{x-2}{11}+\frac{x-2}{12}+\frac{x-2}{13}-\frac{x-2}{14}-\frac{x-2}{15}=0\)

\(=>\left(x-2\right)\left(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}-\frac{1}{14}-\frac{1}{15}\right)=0\)

Mà \(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}-\frac{1}{14}-\frac{1}{15}\ne0\)

\(=>x-2=0\)

\(=>x=2\)

Vậy...