Ta có : \(x-\left\{x-\left[x+x-1\right]\right\}=1\)
\(x-\left\{x-x-x+1\right\}=1\)
\(x-x+x+x-1=1\)
\(2x-1=1\)
\(2x=1+1\)
\(2x=2\)
\(\Rightarrow x=2:2\)
\(x=1\)
\(x-\left\{x-\left[x-\left(-x+1\right)\right]\right\}=1\)
\(x-\left\{x-\left[x+x-1\right]\right\}=1\)
\(x-\left\{x-x-x+1\right\}=1\)
\(x-x+x+x-1=1\)
\(2x-1=1\)
\(2x=2\)
\(x=1\)
Vậy x=1
tim so nguyen x biet:x^2-2x+1=0
1,tim cac so nguyen x,y biet: -2/x=y/3 va x<0<y
2, Tim cac so nguyen x,y biet:x-3/y-2=3/2 va x-y=4
Tim x biet:x(2+x^2)(7-x)=0
tim x biet:x*6+x*7-x/8=5
tim x biet:x+16/9=x/7
tim X biet:x+2/3=X-2/2
tim x biet:
x - 36 : 18 = 12
(x - 36) : 18 = 12
tim x,y biet:x+3/y+5=3/5 va x+y=16
Giup minh cau nay voi
Tim x biet:x^3-x^2=0
