a, \(\left(2x+3\right)^2=\frac{3^2}{11^2}\)
từ đó suy ra
\(2x+3=\frac{3}{11}\)
2x=3/11-3
2x=-2/8/11
x=-2/8/11:2
x=-1/4/11
b,
(3x-1)^3=-8/27
(3x-1)^3=(-2/3)^3
Vậy suy ra
3x-1=-2/3
3x=-2/3+1
3x=1/3
x=1/3:3
x=1/9
Tìm x:
a)\(2.\left(3x-\frac{1}{2}\right)-2x=\frac{1}{2}\left(2x-3\right)\)
b)\(\left(2x-\frac{3}{5}\right)^2=\frac{4}{25}\)
c)\(\left(3x-1\right)^3=27\)
d)\(5-\left|x\right|=2\)
e)|2x+1|-3=3
f)|3-2x|=5
\(\left(5-x\right)\left(3x-\frac{1}{4}\right)=0\)
Câu 1: Tìm x
1/\(\frac{1+3x}{2}=\frac{7}{3}-\frac{x+1}{6}\)
2,\(\left|\frac{2x+1}{3}\right|=\left|\frac{x-1}{5}\right|\)
3,\(\left(\frac{4}{3}+2x\right)^3=\frac{8}{-27}\)
Rút gọn: a)\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}.12^{10}}\)
b)\(\frac{\left(-\frac{1}{2}\right)^3-\left(\frac{3}{4}\right)^3.\left(-2\right)^2}{2.\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}}\)
Tìm x
a)\(3^{x+1}=9^x\)
b)\(2^{3x+2}=4^{x+5}\)
c)\(3^{2x-1}=243\)
Tìm x:
a)\(\left(2x+3\right)^2=\frac{9}{21}\)
b)\(\left(3x-1\right)^3=\frac{-8}{27}\)
c)\(x^{10}=25.x^8\)
d)\(\left(x^4\right)^2=\frac{x^{12}}{x^{15}}\)
e)\(\left(x+3\right)^3=\left(x+3\right)^5\)
Cầu giúp đỡ~
1. Tìm x, biết:
a) \(\frac{x}{-15}=\frac{-60}{x}\)
b) \(\frac{-2}{x}=\frac{-x}{\frac{8}{25}}\)
c) \(3,8:\left(2x\right)=\frac{1}{4}:2\frac{2}{3}\)
d) \(1\frac{1}{3}:0,8=\frac{2}{3}:\left(0,1x\right)\)
2. Tìm x,y, biết: \(\frac{x}{12}=\frac{y}{24}\)và x.y=98
3. Tìm x, biết:
a) \(\left(2x+3\right)^2=\frac{9}{121}\)
b) \(\left(3x-1\right)^3=\frac{-8}{27}\)
Bài 1 : Tìm x biết :
a, \(\left|\frac{3}{2}x+\frac{1}{2}\right|=\left|4x-1\right|\)
b, \(\left|\frac{5}{4}x-\frac{7}{2}\right|-\left|\frac{5}{8}x+\frac{3}{5}\right|=0\)
c,\(\left|\frac{7}{5}x+\frac{2}{3}\right|=\left|\frac{4}{3}x-\frac{1}{4}\right|\)
Bài 2 : Tìm x biết :
a, | 2x - 5 | = x +1
b, | 3x - 2 | -1 = x
c, | 3x - 7 | = 2x + 1
d, | 2x-1 | +1 = x
Tìm x :
a ) \(x^{10}\)= \(25x^8\)
b ) \(\left(2x+3\right)^2\)= \(\frac{9}{121}\)
c ) \(\left(3x-1\right)^3\)= \(-\frac{8}{27}\)
a/A=1+2-3-4+5+6-7-8+....+2001+2002-2003
b/B=\(\left(\frac{1}{4}-1\right)\left(\frac{1}{9}-1\right)\left(\frac{1}{16}-1\right)\left(\frac{1}{25}-1\right)...\left(\frac{1}{121}-1\right)\)
tìm số nguyên x, biết:
a, \(\left(\frac{1}{5}\right)^x=\left(\frac{1}{125}\right)^3\)
b, \(\left(\frac{3}{5}\right)^x=\left(\frac{9}{25}\right)^3\)
c,\(2^{3-2x}=8^3\)
d, \(2^{3x+1}=32^2\)
e, \(3^{6-3x}=81^3\)
