Question

tìm x

65-4^x+2=2014⁰

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Answer 1

\(65-4^{x+2}=2014^0\)

\(4^{x+2}=65-1\)

\(4^{x+2}=64\)

\(4^{x+2}=4^3\)

\(\Rightarrow x+2=3\)

\(x=1\)

Vậy \(x=1\)

Tham khảo nhé~

Answer 2

    65 - 4^ x+2 = 2014^0

=>65 - 4^x+2=1

=>       4^x+2=65-1

=>       4^x+2=64

=>       4^x+2=4^3

=>       4^x    =4^3-2

=>       4^x    =4^1

=>           x    =1

Answer 3

có : 

65 - 4^x+2 = 2014⁰

65 - 4^x+2=1

4^x+2  = 64

4^{x + 2} = 4³

x+2 = 3 

x = 1

vậy x = 1

Answer 4

      \(65-4^{x+2}=2014^0\)

\(\Leftrightarrow65-4^{x+2}=1\)

\(\Leftrightarrow4^{x+2}=65-1\)

\(\Leftrightarrow4^{x+2}=64\)

\(\Leftrightarrow4^{x+2}=4^3\)

\(\Leftrightarrow x+2=3\)

\(\Leftrightarrow x=1\)

     Vậy \(x=1\)

                         ~~~~~~~~Hok tốt~~~~~~~~

Answer 5

\(65-4^{x+2}=2014^0\)

\(\Rightarrow65-4^{x+2}=1\)

\(\Rightarrow4^{x+2}=65-1\)

\(\Rightarrow4^{x+2}=64\)

\(\Rightarrow4^{x+2}=4^3\)

\(\Rightarrow x+2=3\)

\(\Rightarrow x=3-2\)

\(\Rightarrow x=1\)

Vậy x = 1

_Chúc bạn học tốt_