Question

tim x:

5(x² - 3x + 1) + x(1 - 5x) = x-2

giup mik vs ah

Answer 1

Ta có : 5(x² - 3x + 1) + x(1 - 5x) = x - 2

=> 5x² - 15x + 5 + x - 5x² = x - 2

=> -14x + 5 = x - 2

=> -15x = -7

=> x = 7/15

Vậy x = 7/15 

Answer 2

\(5\left(x^2-3x+1\right)+x\left(1-5x\right)=x-2\)

\(\Leftrightarrow5x^2-15x+5+x-5x^2-x=-2\)

\(\Leftrightarrow\left(5x^2-5x^2\right)+\left(-15x+x-x\right)=-2-5\)

\(\Leftrightarrow-15x=-7\)

\(\Leftrightarrow x=\frac{7}{15}\)

Answer 3

5( x² - 3x + 1 ) + x( 1 - 5x ) = x - 2

<=> 5x² - 15x + 5 + x - 5x² = x - 2

<=> -14x + 5 = x - 2

<=> -14x - x = -2 - 5

<=> -15x = -7

<=> x = 7/15