`->` \(\left[{}\begin{matrix}5x-1=\dfrac{6}{7}\\5x-1=-\dfrac{6}{7}\end{matrix}\right.\)
`->` \(\left[{}\begin{matrix}x=\dfrac{13}{35}\\x=\dfrac{1}{35}\end{matrix}\right.\)
`->` \(\left[{}\begin{matrix}5x-1=\dfrac{6}{7}\\5x-1=-\dfrac{6}{7}\end{matrix}\right.\)
`->` \(\left[{}\begin{matrix}x=\dfrac{13}{35}\\x=\dfrac{1}{35}\end{matrix}\right.\)
tìm x, biết:
(5x+1)^2=36/49
tìm x biết: (5x+1)2 = 36/49
Tìm x biết:
(5x + 1)2 = 36/49
Tìm x
( 5x + 1)2 = 36/49
Nhanh mk tick
Tìm x, biết:
a) ( 5x+1)^2+36/49
b) (x-2/9)^3=(2/3)^6
c) (8x-1)^2n+1=5^2n+1
tìm x thuộc z :
\(\left(5x+1\right)^2=\frac{36}{49}\)
Tìm x,y: (5x+1)^2=36/49=(2y-1)^3
(x-2/9)^3=(2/3)^6=(y/3)^2
(8x-1)^2y+1=5^2y+1 (với y thuộc N)
\(5x-9=5+3x;2^3+0,5x=1,5;\left(5x+1\right)^2=\dfrac{36}{49};\left(\dfrac{-3}{81}\right)^x=-27;2^{x-1}=16\)
gia tri x thoa man (5x + 1 )^2=36/49
mong mọi người giúp mình
1) tìm x
a) ( x . 1/3 ) 2 = 1/36
b) ( 5x + 1 ) 2 = 36/49
c) ( x - 2/9 ) 3 = ( 2/3 ) 6