3.(x+3)2+(2x-1)2-7(x-3)=36
=>3x2+18x+27+4x2-4x+1-7x+21=36
=>7x2+7x+49=36
=>7x2+7x+49-36=0
=>7x2+7x+13=0
\(\Rightarrow7\left(x+\frac{1}{2}\right)^2+\frac{45}{4}>0\)với mọi x ->vô nghiệm
Tìm x:
a) 3.(x-1)^2-3x.(x-5)=1
b) 3.(x+2)^2+(2x-1)^2-7.(x-3)(x+3)=36
tìm x , bt :
\(3\left(x+2\right)^2+\left(2x-1\right)^2-7\left(x+3\right)\left(x-3\right)=36\)36
Áp dụng hằng đẳng thức tìm x
Tìm x,y:
(y-2).(y-3)+(y-2)-1=0
x^3+27+(x+3)(x-9)=0
2(x+3)-x^2-3x=0
(x-7)(x+3)=(x+3)(2x-9)
36-x^2+2x-1=0
Tìm x , biết :
A / ( 2x+1 )^2 - 4 ( x+2 )^2 = 9
B / ( x+3)^2 - ( x-4 ) . ( x+8 ) = 1
C / 3.( x+2 )^2 + ( 2x-1 ) - 7 ( x+3 ) . ( x-3 ) = 36
-- Ai giúp Trân , Trân sẽ tick cho --
bài 1 : tìm x
a)(2x+1)-4(x+2)2 =99
b)(x+3)2-(x-4)(x+8)=1
c)3(x+2)2+(2x-1)2-7(x+3)(x-3)=36
Tìm x,y :
a)(y-2).(y-3)+(y-2)-1=0
b)x^3+27+(x+3).(x-9)=0
c)2(x+3)-x^2-3x=0
d)(x-7).(x+3)=(x+3.(2x-9)=0
e)36-x^2+2x-1=0
tim x biet
(2x=1)^2 - 4(x=2)^2=9
3(x-1)^2 -3x(x-5)=1
3(x+2)^2+ (2x-1)^2 =7
7(x+3)(x-3)=36
Tìm x biết
a) (x + 3)2 - (x - 4) (x + 8) = 1
b) 3 (x+2)2 + (2x - 1)2 - 7 (x + 3) (x - 3) = 36
tìm x:
a) (2x+1)^2-4(x+2)^2=9
b)3(x-1)^2-3x(x-5)=21
c)(x+3)^2-(x-4)(x+8)=1
d)3(x+2)^2+(2x-1)^2=7(x+3)(x-3)=36
e)(x-1)(x^2+x+1)-x(x+2)(x-2)=5
f)(x-1)^3 -(x+3)(x^2-3x+9)+3(x^3-4)=2
