Question

tìm x

\(3^{x+2}+4.3^{x+1}+3^{x-1}=6^6\)

Answer 1

\(3^{x+2}+4.3^{x+1}+3^{x-1}=6^6\)

\(3^{x-1}.3^3+4.3^{x-1}.3^2+3^{x-1}=6^6\)

\(3^{x-1}.\left(27+9.4+1\right)=6^6\)

\(3^{x-1}.\left(27+36+1\right)=2^6.3^6\)

\(3^{x-1}.64=3^{x-1}.2^6=3^6.2^6\)

\(\Rightarrow\)\(3^6=3^{x-1}\Rightarrow x=7\)

Answer 2

3^x.3^2+4.3^x.3+3^x:3=6^6

3^x.9+4.3^x.3+3^x/3=36

nhóm lại mà làm nhé.

k nha

Answer 3

Vãi thanh niên \(6^6=36\)

Answer 4

à mình quên mất. Mình lại lấy 6.6=36 nên là sai

haizz