\(2^x+2^{x+3}=72\)
\(\Rightarrow2^x\cdot\left(1+2^3\right)=72\)
\(\Rightarrow2^x\cdot9=72\)
\(\Rightarrow2^x=72:9\)
\(\Rightarrow2^x=8\)
\(\Rightarrow2^x=2^3\)
\(\Rightarrow x=3\)
Bai 1 tim x
2/3 x -3/2 x=5/12
72-3/x+1/=9
7/9 : (2+3/4 x)+5/9=23/27
tim x
1/5 + 2/30 + 121/165 < hoặc = x < hoặc = 1/2 + 156/72 + 1/3
Tim cac so nguyen x,y biet:a)*x2 -3*x+1 chia het cho x+2 b)x2-xy = 5x-4y-9 c) (x2-8)*(x2-15)<0 d) (x+1)2+(y+1)2+(x-y)2=2 e) (x2-4)x2>0 ai lam truoc minh tick,mai minh di hoc rui,lam giup minh di pls Thank ban truoc ne ;(
Tim x biet : a) 5-|x-2|+x=0. (b) |x-1|+2-x=72
c,31 . 72 - 31 x 70 - 31 x2 - 31
d, 25 x 32 - 47 - 32 x ( 25 - 47 )
e, (- 3 ) ^2 + 3^3 - ( 3)^0
g, 125 x ( -61) x ( - 2 )^3 x ( - 1 ) ^ 2n
1.Tim x,biết
a)2.x-138=23.32
b)231-(x-6)=1339÷13
c)[(6.x-72)÷2-84].28=5628
tim x biet :
a) 1/3 + 1/6 +1/10+ ...+ 2/ x*(x+1)
b) 1/2 + 1/6 +1/12 + ...+1/x=72/73
Cau 1:
Tim x, biet: 1-4+7-10+.............-x=-75
Cau 2:
Cho x1, x2, x3, x4, x5 thuộc Z
Biết x1+ x2 + x3 + x4 + x5=0
và x1 + x2=x3+ x4= x4 + x5 =2
Tinh x3, x4 , x5
Cau 3: Tim x biet
(x+7+1) chia het cho (x+7)
tim x
[(6.x-72).2-84].28=5628
