Question

Tìm x

(2x-1)¹² = (x+1)¹²

Answer 1

Ta có: \(\left(2x-1\right)^{12}=\left(x+1\right)^{12}\)

=> \(\orbr{\begin{cases}2x-1=x+1\\2x-1=-x-1\end{cases}}\)

=> \(\orbr{\begin{cases}2x-x=1+1\\2x+x=-1+1\end{cases}}\)

=> \(\orbr{\begin{cases}x=2\\3x=0\end{cases}}\)

=> \(\orbr{\begin{cases}x=2\\x=0\end{cases}}\)

Vậy ...

Answer 2

\(\left(2x-1\right)^{12}=\left(x+1\right)^{12}\)

\(\Leftrightarrow\orbr{\begin{cases}2x-1=x+1\\2x-1=-\left(x+1\right)\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x-x=1+1\\2x+x=-1+1\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=2\\3x=0\end{cases}}\)          \(\Leftrightarrow\orbr{\begin{cases}x=2\\x=0\end{cases}}\)

Vậy : \(x\in\left\{2;0\right\}\)

Rất vui vì giúp đc bạn !!!