1)
Ta có: \(\left(x-\frac{1}{2}\right)^3=8\Rightarrow\left(x-\frac{1}{2}\right)^3=2^3\)
\(\Rightarrow x-\frac{1}{2}=2\Rightarrow x=2+\frac{1}{2}=\frac{5}{2}\)
\(\left(x-1\right)^3=\frac{8}{27}\Rightarrow\left(x-1\right)^3=\left(\frac{2}{3}\right)^3\)
\(\Rightarrow x-1=\frac{2}{3}\Rightarrow x=\frac{2}{3}+1=\frac{5}{3}\)
\(\left(x-\frac{1}{2}\right)^3=8\)
\(\left(x-\frac{1}{2}\right)^3=2^3\)
\(x-\frac{1}{2}=2\)
\(x=2+\frac{1}{2}\)
\(x=\frac{5}{2}\)
1
(x - 1/2)^3 = 8
(x - 1/2)^3 = 2^3
x - 1/2 =2
x = 5/2
2
( x - 1)^3 = 8/27
( x - 1)^3 = (2/3)^3
x - 1 = 2/3
x=5/3
3
(x-2/3)^x=(1/81)^1=(1/9)^2
Thay x=1; x=2 không có kết quả thỏa mãn
Nên không có x thỏa mãn
1/ (x-1/2)^3=8
(x-1/2)^3=2^3
<=> x-1/2=2
x= 2+1/2
x= 4/2+1/2
x=5/2
(x-1)^3=8/27
(x-1)^3=(2/3)^3
<=>x-1=2/3
x= 2/3+1
x=2/3+3/3
x=5/3
(x-2/3)^x=1/81
x=