Question

Tìm x, y, z

10x = 6y và 2x^2 - y^2 = 16

Answer 1

10x=6y

=> \(\frac{x}{6}=\frac{y}{10}\)

= \(\frac{x^2}{36}=\frac{y^2}{100}\)

= \(\frac{2x^2}{72}=\frac{y^2}{100}=\frac{2x^2-y^2}{72-100}=\frac{16}{-28}=\frac{-4}{7}\)

=> x= -4/7.6= -24/7

=> y= -4/7.10=-40/7

Answer 2

10x = 6y <=> 5x = 3y \(\Rightarrow\frac{x}{3}=\frac{y}{5}\) 

\(\Rightarrow\frac{2x^2}{18}=\frac{y^2}{25}=\frac{2x^2-y^2}{18-25}=\frac{16}{-7}=\)...

(số hơi lẻ)