Ta có : \(\frac{3}{x}=\frac{-36}{84}=\frac{3}{7}\) => \(x=7\)
\(\frac{y}{35}=\frac{-36}{84}=\frac{3}{7}\)=> \(7y=3\cdot35\)=> \(y=\frac{3\cdot35}{7}=15\)
\(y=\frac{-36\times35}{84}=-15\)
\(x=\frac{35\times3}{-15}=-7\)
Vậy................
Ta có \(\frac{y}{35}=-\frac{36}{84}\)
\(\Rightarrow84y=-36.35\)
\(\Rightarrow84y=-1260\)
\(\Rightarrow y=-15\)
Thay y = -15 ta có \(\frac{3}{x}=\frac{-15}{35}\)
\(\Rightarrow\frac{3}{x}=\frac{-3}{7}\)
\(\Rightarrow-3x=21\)
\(\Rightarrow x=-7\)