tìm cặp số tự nhiên sao cho:
a, \(\frac{4}{x}-\frac{y}{3}=\frac{5}{6}\)( x, y thuộc N )
b, \(\frac{5}{x}-\frac{y}{3}=\frac{1}{6}\) ( x , y thuộc Z )
c, \(\frac{x}{6}_{ }-\frac{2}{y}=\frac{1}{30}\) ( x, y thuộc Z )
Tìm các số nguyên x,y sao cho
a,\(\frac{x}{3}=\frac{5}{y}\)
b,\(\frac{3}{x}+\frac{y}{3}=\frac{5}{6}\)
c,\(\frac{5}{x}-\frac{y}{3}=\frac{1}{6}\)
d,\(\frac{x}{6}-\frac{2}{y}=\frac{1}{30}\)
Tìm \(x,y\in Z\)biết
a) \(\frac{3}{x}+\frac{y}{3}=\frac{5}{6}\)
b)\(\frac{5}{x}-\frac{y}{3}=\frac{1}{6}\)
c)\(\frac{x}{6}+\frac{2}{y}=\frac{1}{30}\)
d)\(xy+2x-y=15\)
tìm các cặp số nguyên x,y sao cho:
a)\(\frac{x}{3}-\frac{4}{y}=\frac{1}{5}\)
b)\(\frac{5}{x-1}-\frac{y-1}{3}=\frac{1}{6}\)
c)\(\frac{x}{2}+\frac{y}{3}=\frac{x+y}{2+3}\)
1) \(\frac{24}{-12}=\frac{x}{5}=\frac{-y}{3}\)Tìm x và y
2) \(\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-5}{25}\le\frac{x}{10}< \frac{-3}{4}+\frac{4}{14}+\frac{-2}{8}+\frac{-3}{5}+\frac{5}{7}\)Tìm x
3) \(\frac{8.x+18}{2.x+6}\)Tìm x
Tim x,y\(\in\) z biet :
a)\(\frac{x}{3}-\frac{2}{y}=\frac{1}{5}\) b)\(\frac{2}{x}-\frac{y}{3}=\frac{5}{6}\)
c)\(\frac{5}{x}-\frac{y}{3}=\frac{1}{6}\) d) \(\frac{x}{6}-\frac{2}{y}=\frac{1}{4}\)
1, Tìm số nguyên x,y
a,\(\frac{3}{x}+\frac{y}{3}=\frac{5}{6}\)
b,\(\frac{x}{3}-\frac{4}{y}=\frac{1}{5}\)
c,\(\frac{x}{2}+\frac{y}{3}=\frac{x+y}{2+3}\)(x,y thuộc N)
Bài 1 : Tính :
B = \(\frac{\frac{1}{2}+\frac{3}{4}-\frac{5}{6}}{\frac{1}{4}+\frac{3}{8}-\frac{5}{12}}+\frac{\frac{3}{4}+\frac{3}{5}-\frac{3}{8}}{\frac{1}{4}+\frac{1}{5}-\frac{1}{8}}\)
Bài 2 : tìm x và y
a) x3 - 36x = 0
b) \(\frac{x-3}{y-2}=\frac{3}{2}\)và x - y = 4 ( x , y \(\in\)Z )
tìm x,y \(\in\)N ,biết :
a, \(\frac{3}{4}< \frac{x}{30}< \frac{y}{60}< \frac{4}{5}\)
b, \(\frac{-1}{2}< \frac{x}{24}< \frac{y}{12}< \frac{-3}{8}\)
c, \(\frac{-7}{8}< \frac{x}{38}< \frac{y}{72}< \frac{-5}{6}\)