Question

Tìm x : \(x^3-x=0\)

Answer 1

\(x^3-x=0\)

\(\Leftrightarrow x\left(x^2-1\right)=0\)

\(\Leftrightarrow x\left(x-1\right)\left(x+1\right)=0\)

\(\Leftrightarrow\hept{\begin{cases}x=0\\x-1=0\\x+1=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=0\\x=1\\x=-1\end{cases}}}\)

Vậy \(S=\left\{-1;0;1\right\}\)

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Answer 2

x³ - x = 0

=> x.(x² - 1) = 0

=> \(\orbr{\begin{cases}x=0\\x^2-1=0\end{cases}}\)=> \(\orbr{\begin{cases}x=0\\x^2=1\end{cases}}\)=> \(\orbr{\begin{cases}x=0\\x\in\left\{1;-1\right\}\end{cases}}\)

Answer 3

x³-x=0

=> x(x²-1)=0

=> x(x-1)(x+1)=0

=> x= 0 hoặc x=1 hoặc x=-1