` x^2 - x = -1/4 `
` => x^2 - x - ( -1/4) = 0 `
` => x^2 - x + 1/4 = 0 `
` ( x - 1/2)^2 = 0 `
` => x - 1/2 = 0 `
` => x = 1/2 `
Vậy ` x = 1/2 `
x2 - x = -1/4
x( x - 1 ) = -1/4
Chia thành 2 trường hợp :
TH1 : x = -1/4
TH2 : x - 1 = -1/4
x = (-1/4) + 1
x = 3/4
Vậy x ∈ { -1/4; 3/4}