\(x^2-4=2\left(x^2+4x+4\right)\)
⇔\(x^2-4=2x^2+8x+8\)
⇔\(x^2-4-2x^2-8x-8=0\)
⇔\(-x^2-12-8x=0\)
⇔\(\left(x+2\right)\left(x+6\right)=0\)
⇔\(\left[{}\begin{matrix}x+2=0\\x+6=0\end{matrix}\right.\)
⇒ \(\left[{}\begin{matrix}x=0-2=-2\\x=0-6=-6\end{matrix}\right.\)
Vậy \(x\) ∈ \(\left\{-2;-6\right\}\)
\(\#PeaGea\)
tìm x:
a.(x-3)^4-(x+3)^4+24x^3=216
b.(2x+1)(16x^4-8x^3+4x^2-2x+1)-(2x-1)(16x^4+8x^3+4x^2+2x+1)=2
tìm GTNN của bt:
x^2+2x+4
x^2-x-5/3/4
4x^2-x-3/16
Tìm x, biết:
A) (x -1)^3+(2-x)(4+2x+x^2)+3x(x+2)=17
B) (x+2)(x^2-2x+4)-x(x^2-2)=15
C) (5x-2)(5x+2)-(5x+3)(5x-4)=8
D) (4x-3)(4x+2)+(4x+5)(1-4x)=2.5^2
Tìm GTNN:
a) \(\dfrac{1}{-x^2+2x-4}\)
b) \(\dfrac{12}{12x-4x^2-13}\)
c) \(\dfrac{x^2-4x-4}{x^2-4x+5}\)
d) \(\dfrac{15}{-6x^2-5y^2+10xy-4x+10y-19}\)
e)\(\dfrac{x^2-2011}{4.\left(x^2+1\right)}\)
Tìm x biết :
x^4-4x^3+4x^2-(2x-4)(x^2-2x)+(2-x)^2=0
Tìm x 2.(5x-8)-3(4x-5)=4(3x-4)+11 3 . 2(x³-1)-2x²(x+2x⁴)+(4x⁵+4)x=6
tìm x biết
1) x^2 + 4x + 4 = 0
2) x^2 + 4x + 4 =0
3) (x + 1)^2 + 2 (x + 1) = 0
mọi người giải chi tiết giúp mình nha :3
A= 1/x+2 - x^3-4x/x^2+4 .(1/x^2+4x+4 +1/4-x^2) a) tìm TXĐ,R/G A b) x=? để A>0;A<0;A=0 GIÚP MIK VS MIK ĐAG CẦN GẤP
Bài 1: Tìm x
a) (x-1)^3+3(x+1)^2=(x^2-2x+4)(x+2)
b) x^2-4=8(x-2)
c) x^2-4x+4=9(x-2)
d) 4x^2-12x+9=(5-x)^2
tìm x,y thuộc Z:
1) y^2+y=x^4+x^5+x^2+x
2) x^4 +4x^3 +6x^2 +4x =y^2
