\(x+\dfrac{40}{27}=2\)
\(x=\dfrac{14}{27}\)
\(x+1+\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+\dfrac{1}{81}=2\)
\(\Leftrightarrow x+\dfrac{121}{81}=2\)
hay \(x=\dfrac{41}{81}\)
\(x+\dfrac{40}{27}=2\)
\(x=\dfrac{14}{27}\)
\(x+1+\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+\dfrac{1}{81}=2\)
\(\Leftrightarrow x+\dfrac{121}{81}=2\)
hay \(x=\dfrac{41}{81}\)
1. \(\left(y+\dfrac{1}{3}\right)\)+\(\left(y+\dfrac{1}{9}\right)\)+\(\left(y+\dfrac{1}{27}\right)\)+\(\left(y+\dfrac{1}{81}\right)\)=\(\dfrac{56}{81}\)
2. 18:\(\dfrac{Xx0,4+0,32}{X}\)+5=14
3. \(\dfrac{3xX}{2}\)=\(\dfrac{2}{5}+\)X\(+\dfrac{1}{3}\)
4. X-\(\dfrac{11}{15}\)=\(\dfrac{3+X}{5}\)
\(\left(x+\dfrac{1}{3}\right)+\left(x+\dfrac{1}{9}\right)+\left(x+\dfrac{1}{27}\right)+\left(x+\dfrac{1}{81}\right)=\dfrac{56}{81}\)
\(\dfrac{1}{3}\)+\(\dfrac{1}{9}\)+\(\dfrac{1}{27}\)+\(\dfrac{1}{81}\)+\(\dfrac{1}{243}\)+\(\dfrac{1}{720}\)
Bài 1:
\(a,\dfrac{1}{5}+\dfrac{1}{10}+\dfrac{1}{20}+\dfrac{1}{40}+...............+\dfrac{1}{1280}\)
\(b,\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+\dfrac{1}{81}+..............+\dfrac{1}{59049}\)
\(c,\dfrac{1}{2}\times3+\dfrac{1}{3}\times4+\dfrac{1}{4}\times5+\dfrac{1}{5}\times6\)
\(A=1+\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+\dfrac{1}{81}+\dfrac{1}{243}+\dfrac{1}{729}\)
Tính A
3\(\dfrac{1}{11}\) x \(\dfrac{27}{46}\) x 1\(\dfrac{6}{17}\) x 2 \(\dfrac{4}{9}\)
tìm x
a) \(1\dfrac{1}{2}:x=\dfrac{1}{2}\) b)\(\dfrac{7}{9}-x=\dfrac{2}{3}\) c)\(\dfrac{8}{7}:x=\dfrac{6}{7}\) d)\(\dfrac{9}{5}-x=\dfrac{3}{7}\)
S = \(81\) + \(27\) + \(9\) + \(3\) ... + \(\dfrac{1}{27}\) + \(\dfrac{1}{81}\)
Tính S giúp mik với ạ, ai nhanh mik tick
TÍNH:
1+\(\dfrac{1}{3}\)+\(\dfrac{1}{9}\)+\(\dfrac{1}{27}\)+\(\dfrac{1}{81}\)
AI BÍT TÍNH NHANH BÀI NÀY NỮA THÌ CHỈ MÌNH VỚI !!!!!
(Òwó)❤❤❤