Question

Tìm x :

(x+1/2).(x-3/4)=0

Answer 1

\(\left(x+\frac{1}{2}\right).\left(x-\frac{3}{4}\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{2}=0\\x-\frac{3}{4}=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=\frac{3}{4}\end{cases}}\)

\(\Rightarrow x\in\left\{-\frac{1}{2};\frac{3}{4}\right\}\)

Answer 2

\(\left(x+\frac{1}{2}\right).\left(x-\frac{3}{4}\right)=0\)

=> \(\orbr{\begin{cases}x+\frac{1}{2}=0\\x-\frac{3}{4}=0\end{cases}}\)=> \(\orbr{\begin{cases}x=\frac{-1}{2}\\x=\frac{3}{4}\end{cases}}\)

Vậy \(x\in\left\{\frac{-1}{2};\frac{3}{4}\right\}\)