\(x.\left(x-2015\right)-\left(x-2015\right)=0\)
\(\left(x-1\right)\left(x-2015\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-1=0\\x-2015=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=2015\end{cases}}\)
\(x\cdot\left(x-2015\right)-x+2015=0\)
\(x\cdot\left(x-2015\right)-\left(x-2015\right)=0\)
\(\left(x-2015\right)\cdot\left(x-1\right)=0\)
\(\orbr{\begin{cases}x-2015=0\\x-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2015\\x=1\end{cases}}}\)
Ta có : x( x - 2015 ) - x + 2015 = 0
\(\Rightarrow\)x( x - 2015 ) - ( x - 2015 ) = 0
\(\Rightarrow\)( x - 2015 )( x - 1 ) = 0
\(\Leftrightarrow\)x - 2015 = 0 hoặc x - 1 = 0
\(\Rightarrow\)x = 2015 hoặc x = 1
Vậy : x = 2015 hoặc x = 1
thank các bạn nha hc tốt
