(x-1/2)(4-x)=0
=>x-1/2=0 hay 4-x=0
x=0+1/2 x=4-0
x=1/2 x=4
Vậy x=1/2 hoặc x=4
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1 tìm x biết ;a, 0-|x + 1| 5 b, 2 - | frac{3}{4}- x | frac{7}{12}c, 2 | frac{1}{2}x - frac{1}{3}| - frac{3}{2} frac{1}{4}d, | x - frac{1}{3}| frac{5}{6}e, frac{3}{4}- 2 | 2x - frac{2}{3}| 2f, frac{2x-1}{2} frac{5+3x}{3}
Đọc tiếp
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1 tìm x biết ;a, 0-|x + 1| 5 b, 2 - | frac{3}{4}- x | frac{7}{12}c, 2 | frac{1}{2}x - frac{1}{3}| - frac{3}{2} frac{1}{4}d, | x - frac{1}{3}| frac{5}{6}e, frac{3}{4}- 2 | 2x - frac{2}{3}| 2f, frac{2x-1}{2} frac{5+3x}{3}
Đọc tiếp
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
!.TÌm x, biết
a) x.(x-2)=0
b) \(\left(\frac{1}{2}+\frac{2}{3}-\frac{1}{4}\right).\left(X-3\right)=0\)
c) (X-10).(X-20)=0
d) (x-2).(x^2-1)=0
e) 2|4-x|=|-8|
Tìm x:
a) \(\frac{-15}{12}x+\frac{3}{7}=\frac{6}{4}x-\frac{1}{2}\)
b) \(\frac{2}{5}\left(x+1\right)-\frac{4}{5}x=0\)
bài 1 : tìm x:
\(4\left(x-\frac{1}{4}\right)-3\left(x+\frac{2}{3}\right)=0\)
a)\(\frac{1}{6}x+\frac{1}{10}-\frac{4}{15}x+1=\)\(0\)
b)\(\left(\frac{1}{7}x-\frac{2}{7}\right).\left(-\frac{1}{5}x+\frac{3}{5}\right).\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)
c)\(\frac{1}{2}x-\frac{11}{15}:\frac{33}{35}=-\frac{1}{3}\)
Tìm x biết:
tìm x biết : \(4\left(x-\frac{1}{4}\right)-3\left(x+\frac{2}{3}\right)=0\)
1,Tìm x:
a,3x-2=0
b,2x-1=0
c,5.(4+2x)=8+5x
d,\(\frac{1}{2}+\frac{3}{4}x=6-\frac{4}{5}x\)
e,3+2x=4-8x
f,\(5+\frac{1}{2}.\left(x+5\right)=3\)
tìm x biết
\(\frac{1}{3}x+\frac{2}{5}\left(x+1\right)=0\)
\(20\%x+\frac{2}{5}x=x-4\)
Tìm x:
\(\left(\frac{1}{7}x-\frac{2}{7}\right)\left(-\frac{1}{5}x+\frac{3}{5}\right)\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)