Lời giải:
$x-4300-\frac{5250}{1050.250}=4250$
$x-4300-\frac{1}{50}=4250$
$x=4250+\frac{1}{50}+4300=8550,02$
Lời giải:
$x-4300-\frac{5250}{1050.250}=4250$
$x-4300-\frac{1}{50}=4250$
$x=4250+\frac{1}{50}+4300=8550,02$
5.(x+35)=515
(x+40):15=75.12
(x+200):4=460+85:4
x-4300-(5250:1050.250)=4250
x-6-(48-24.2:6-3)=100
20-(7.x-3)+4):3
(6.x-39):3
Tìm x biết:
a)
x-4300-(5250:1050.250)=4250
b)
x-6-(48-24.2:6-3)=100
c)
20-[7.(x-3)+4]=2
d)
[(6x-39):3].28=5628
LÀM RA DÙM MÌNH LUÔN NHA! CẢM ƠN NHIỀU!
cho mình hỏi bài này:
Tìm x biết:
5(x+35)=515
(x+40)nhân 15=75 nhân 12
460+85 nhân 4=(x+200):4
x-4300-(5250:1050 nhân 250)= 4250
x-6-(48-24 nhân 2:6-3)=100
20-[7 nhân (x-3)+4]=2
[(6x-39):3] nhân 28=5628
tìm x
\(\frac{\left(x+1\right)}{15}+\frac{\left(x+2\right)}{14}+\frac{\left(x+3\right)}{13}+\frac{\left(x+4\right)}{12}+\left(x+20\right)=0\)
Tìm x biết :
\(\left(\frac{x-2}{12}\right)+\left(\frac{x-2}{20}\right)+\left(\frac{x-2}{30}\right)+\left(\frac{x-2}{42}\right)+\left(\frac{x-2}{56}\right)+\left(\frac{x-2}{72}\right)=\frac{16}{9}\)
giúp mk nha
Tìm x, biết :
\(\frac{7}{\left(x+3\right)\left(x+10\right)}+\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(x-7\right)\left(x-13\right)}\)
\(+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=\frac{-1}{20}\)
giúp mình với các bạn !!!!!!!!!!!!
Tìm x
1) 70 : \(\frac{4x+720}{x}\) = 1/2
2) \(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\) Với x không thuộc { -2; -5; -10; -17 }
Tìm x biết : \(\frac{\left|x-2\right|}{12}+\frac{\left|x-2\right|}{20}+\frac{\left|x-2\right|}{30}+\frac{\left|x-2\right|}{42}=\frac{70^5}{2^3\cdot21^6}\)
Tìm x, biết:
\(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\left(x\notin-2;-5;-10;-17\right)\)
\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=-\frac{3}{4}\)
Với \(x\notin1;3;8;20\)
\(\frac{x+1}{10}+\frac{2+1}{11}\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x-148}{8}=0\)