\(\left(x-3\right)^2-4=0\)
=> \(\left(x-3\right)^2=4\)
=> \(\sqrt{\left(x-3\right)^2}=\sqrt{4}=2\)
=> \(\left[{}\begin{matrix}x-3=2\\x-3=-2\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}x=3+2=5\\x=-2+3=1\end{matrix}\right.\)
Vậy \(x\in\left\{5;1\right\}\)