x + \(\frac{1}{3}\) +x-\(\frac{2}{4}\)=5
=> x + 5 = x - 5 + \(\frac{2}{4}-\frac{1}{3}=5\)
=> x + 5 =0,3
=>x= 0,3 + 5
=>0,8
Vậy x=0,8
\(x-\frac{1}{3}+x-\frac{2}{4}=5\)
\(\Leftrightarrow2x=5+\frac{1}{3}+\frac{2}{4}\)
\(\Leftrightarrow2x=\frac{35}{6}\Leftrightarrow x=\frac{35}{12}\)
Vậy \(x=\frac{35}{12}\)