\(\frac{x-2}{4}=\frac{9}{x-2}\)
\(\Leftrightarrow\left(x-2\right)^2=9.4\)
\(\left(x-2\right)^2=36\)
\(\Rightarrow\orbr{\begin{cases}x-2=6\\x-2=-6\end{cases}\Leftrightarrow\orbr{\begin{cases}x=8\\x=-4\end{cases}}}\)
Vậy \(\orbr{\begin{cases}x=8\\x=-4\end{cases}}\)
\(\frac{x-2}{4}=\frac{9}{x-2}\)
<=>(x-2)(x-2)=9.4
<=>(x-2)2=36
<=>(x-2)2=62
=>x-2=-6 hoặc x-2=6
x=-6+2 x=6+2
x=-4 x=8
Vậy x\(\in\){-4;8}
\(\frac{x-2}{4}=\frac{9}{x-2}\)
\(\Rightarrow\left(x-2\right)\left(x-2\right)=9\times4\)
\(\Rightarrow\left(x-2\right)^2=36=6^2\)
\(\Rightarrow x-2=6\)
\(\Rightarrow x=6+2\)
\(\Rightarrow x=8\)
\(\frac{x-2}{4}=\frac{9}{x-2}\)
\(\Leftrightarrow\left(x-2\right)\left(x-2\right)=9.4\)
\(\Leftrightarrow x^2-4x+4=36\)
\(\Leftrightarrow x^2-4x+4=6^2\)
Xét 2 TH:
TH1: x - 2 = -6
=> x = 2 + -6
x = -4
TH2: x - 2 = 6
=> x = 2 + 6
x = 8
\(\Rightarrow\orbr{\begin{cases}x=-4\\x=8\end{cases}}\)