Question

tìm x thuộc z:

a, x-1/9=8/3

b,-x/4=-9/6

c,x/4=18/8

Answer 1

a, \(x-\frac{1}{9}=\frac{8}{3}\)

  \(x\)          \(=\frac{8}{3}+\frac{1}{9}\)

 \(x\)            \(=\) \(\frac{25}{9}\)

b, \(\frac{-x}{4}=\frac{-9}{6}\)

\(\Rightarrow\) \(-x.6=4.\left(-9\right)\)

\(\Rightarrow\) \(-x.6=-36\)

\(\Rightarrow\) \(-x=-36:6\)

\(\Rightarrow\) \(-x=-6\)

\(\Rightarrow\) \(x=6\)

c,  \(\frac{x}{4}=\frac{18}{8}\)

  \(\Rightarrow\) \(x.8=18.4\)

\(\Rightarrow\) \(x.8=72\)

\(\Rightarrow\) \(x=72:8\)

\(\Rightarrow x=9\)

:)

Answer 2

các bạn làm ơn giải bài này cho mình đi mình rất cần vội

Answer 3

a,\(x=\frac{8}{3}+\frac{1}{9}\)

\(x=\frac{25}{9}\)

mk hok ngu,bít lm mỗi ý a thui nha...

mấy ý kia chịu...

Answer 4

\(a)\) \(x-\frac{1}{9}=\frac{8}{3}\)

\(\Leftrightarrow\)\(x=\frac{8}{3}+\frac{1}{9}\)

\(\Leftrightarrow\)\(x=\frac{24+1}{9}\)

\(\Leftrightarrow\)\(x=\frac{25}{9}\)

\(b)\) \(\frac{-x}{4}=\frac{-9}{6}\)

\(\Leftrightarrow\)\(-x=\frac{-3}{2}.4\)

\(\Leftrightarrow\)\(-x=\left(-3\right).2\)

\(\Leftrightarrow\)\(-x=-6\)

\(\Leftrightarrow\)\(x=6\)

\(c)\) \(\frac{x}{4}=\frac{18}{8}\)

\(\Leftrightarrow\)\(x=\frac{9}{4}.4\)

\(\Leftrightarrow\)\(x=9\)

Vậy ... 

Answer 5

a) x−19 =83 

⇔x=83 +19 

⇔x=24+19 

⇔x=259 

b) −x4 =−96 

⇔−x=−32 .4

⇔−x=(−3).2

⇔−x=−6

⇔x=6

c) x4 =188 

⇔x=94 .4

⇔x=9

Answer 6

\(c,\frac{x}{4}=\frac{18}{8}\)

\(x=\frac{18\times4}{8}\)

\(x=9\)

Answer 7

cảm ơn các bạn nhiều