Ta có :\(\frac{x-1}{-2}=\frac{-8}{x-1}\Rightarrow\left(x-1\right)^2=16\Rightarrow\orbr{\begin{cases}x-1=4\\x-1=-4\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-3\end{cases}}}\)
\(\frac{x-1}{-2}=\frac{-8}{x-1}\left(x\ne1\right)\)
\(\Leftrightarrow\left(x-1\right)\left(x-1\right)=-2\cdot\left(-8\right)\)
\(\Leftrightarrow\left(x-1\right)^2=16\)
\(\Leftrightarrow\orbr{\begin{cases}x-1=4\\x-1=-4\end{cases}\Leftrightarrow\orbr{\begin{cases}x=5\\x=-3\end{cases}\left(tm\right)}}\)
Vậy x=5; x=-3
\(\frac{x-1}{-2}=\frac{-8}{x-1}\)
\(\Rightarrow\left(x-1\right)\left(x-1\right)=\left(-2\right)\cdot\left(-8\right)\)
\(\Rightarrow\left(x-1\right)^2=16\)
\(\Rightarrow\orbr{\begin{cases}\left(x-1\right)^2=4^2\\\left(x-1^2\right)=\left(-4\right)^2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x-1=4\\x-1=-4\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x=-3\end{cases}}\)
