Question

Tìm X thuộc Z biết X-(X-(X-(-X+1))=1

Answer 1

\(x-\left\{x-\left[x-\left(-x+1\right)\right]\right\}=1\)

\(\Leftrightarrow x-\left[x-\left(2x-1\right)\right]=1\Leftrightarrow-x+1=1-x\Leftrightarrow0x=0\)

Vậy phương trình có vô số nghiệm 

Answer 2

Ta có: \(x-\left\{x-\left[x-\left(-x+1\right)\right]\right\}=1\)

\(\Leftrightarrow x-\left\{x-\left[x+x-1\right]\right\}=1\)

\(\Leftrightarrow x-\left\{x-2x+1\right\}=1\)

\(\Leftrightarrow x-\left\{-x+1\right\}=1\)

\(\Leftrightarrow2x-1=1\)

\(\Leftrightarrow2x=2\)

hay x=1