Question

Tìm x thuộc Z biết : \(x-\left(\frac{5}{6}-x\right)=x-\frac{2}{3}\)

Answer 1

\(x-\left(\frac{5}{6}-x\right)=x-\frac{2}{3}\)

\(x-\frac{5}{6}+x-x=-\frac{2}{3}\)

\(x=\frac{-2}{3}+\frac{5}{6}\)

\(x=\frac{-4}{6}+\frac{5}{6}\)

\(x=\frac{1}{6}\)

Answer 2

\(x-\left(\frac{5}{6}-x\right)=x-\frac{2}{3}\)

\(x-\frac{5}{6}+x=x-\frac{2}{3}\)

\(\Rightarrow x+x-\frac{5}{6}=x-\frac{2}{3}\Rightarrow x+x-x=-\frac{2}{3}+\frac{5}{6}\)

\(\Rightarrow x=\frac{1}{6}\Rightarrow\)x ko tồn tại

Answer 3

\(x-\left(\frac{5}{6}-x\right)=x-\frac{2}{3}\)

\(x-\frac{5}{6}+x=x-\frac{2}{3}\)

\(2x-x=\frac{-2}{3}+\frac{5}{6}\)

\(x=\frac{1}{6}\)

Answer 4

Ta có \(x-\left(\frac{5}{6}-x\right)=x-\frac{2}{3}\)

\(\Rightarrow x-\frac{5}{6}+x=x-\frac{2}{3}\)

\(\Rightarrow2x-\frac{5}{6}=x-\frac{2}{3}\)

\(\Rightarrow2x-x=\frac{-2}{3}+\frac{5}{6}\)

\(\Rightarrow x=\frac{1}{6}\)

Answer 5

\(x-\left(\frac{5}{6}-x\right)=x-\frac{2}{3}\)

\(x-\frac{5}{6}+x=x-\frac{2}{3}\)

\(x+x-x=\frac{5}{6}-\frac{2}{3}\)

\(x=\frac{1}{6}\)