\(3x-\left|2x+1\right|=2\)
\(\Leftrightarrow\left|2x+1\right|=3x-2\)
Th1 : \(2x+1\ge0\Rightarrow x\ge\frac{2}{3}\)
\(\Leftrightarrow2x+1=3x-2\)
\(x=3\left(TM\right)\)
Th2 : \(2x+1< 0\Rightarrow x< -\frac{1}{2}\)
\(\Leftrightarrow2x+1=2-3x\)
\(\Leftrightarrow5x=1\)
\(x=\frac{1}{5}\left(KTM\right)\)
Vậy ....