\(\left(2x-3\right)-\left(x-5\right)=\left(x+2\right)-\left(x-1\right)\Leftrightarrow2x-3-x-5=x+2-x+1\Leftrightarrow x-8=3\Leftrightarrow x=3+8=11\)
`(2x - 3) - (x - 5) = (x + 2) - (x - 1)`
`<=> 2x - 3 - x - 5 = x+2 - x + 1`
`<=> x - 8 = 3`
`<=> x = 11`
Vậy `x = 11`