Question

tìm x là số tự nhiên

(3x+1)^2:8=2

Answer 1

\(\left(3x+1\right)^2:8=2\)

\(\left(3x+1\right)^2=16\)

\(\left(3x+1\right)^2=4^2\)

\(\Rightarrow\orbr{\begin{cases}3x+1=4\\3x+1=-4\end{cases}}\Rightarrow\orbr{\begin{cases}3x=3\\3x=-5\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\x=-\frac{5}{3}\end{cases}}\)

Vậy x = 1 hoặc \(x=-\frac{5}{3}\) .

Answer 2

(3x+1)^2:8=2

(3x+1)^2=8/2

(3x+1)^2=4

(3x+1)^2=4^2

(3x+1)=4

(3x)=4-1

(3x)=3

x=3/3

x=1