đặt VT là A ta đc:
\(3A=3\left(\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{x\left(x+3\right)}\right)\)
\(3A=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+3}\)
\(3A=1-\frac{1}{x+3}\)
\(A=\left(1-\frac{1}{x+3}\right):3\)
thay A vào VT ta đc:\(\left(1-\frac{1}{x+3}\right):3=\frac{6}{19}\)
\(1-\frac{1}{x+3}=\frac{18}{19}\)
\(\frac{1}{x+3}=\frac{1}{19}\)
=>x+3=19
=>x=16
Tìm x
\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x.\left(x+3\right)}=\frac{6}{19}\)
Tìm x biết
\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x.\left(x+3\right)}=\frac{6}{19}\)
Tìm \(x\)
\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x\left(x+3\right)}\)
Tìm x biết:
\(\left(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{97.100}\right)=\frac{0,33.x}{2009}\)
Bài 1: Rút gọn biểu thức
\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}\) \(B=\frac{15.3^{11}+4.27^4}{9^7}\) \(C=\left(125^3.7^5-175^5:5\right):2016^{2017}\)
Bài 2: Tìm x:
a)\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x.\left(x+3\right)}=\frac{6}{19}\)b)\(\left|\frac{3}{13}x^2+\frac{1}{2}\right|-\frac{3}{4}=\frac{5}{6}\)
Bài 1: Rút gọn biểu thức
\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}\) \(B=\frac{15.3^{11}+4.27^4}{9^7}\) \(C=\left(125^3.7^5-175^5:5\right):2016^{2017}\)
Bài 2: Tìm x:
a)\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x.\left(x+3\right)}=\frac{6}{19}\)b)\(\left|\frac{3}{13}x^2+\frac{1}{2}\right|-\frac{3}{4}=\frac{5}{6}\)
Bài này tìm A nhé. Bạn nào làm đc lời giải phép tính đầy đủ mình tick cho.
a) A = \(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{n\left(n+3\right)}<1\)
b) Tìm tất cả các số nguyên x,y biết : \(\frac{x-1}{9}+\frac{1}{3}=\frac{1}{y+2}\)
\(5\frac{8}{7}\): x + ( 1/7) : x + \(3\frac{1}{17}\): \(17\frac{1}{3}\)= 4/17
\(\frac{1}{1.4}+\frac{1}{4.7}\)\(+\frac{1}{7.10}\)+....+ \(\frac{1}{x\left(x+3\right)}\)= \(\frac{6}{19}\)
Tìm x
\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x\left(x+3\right)}=\frac{125}{376}\)VỚI X thuộc N*
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+...+\frac{1}{x\left(2x+1\right)}=\frac{1}{10}\)VỚI X thuộc N*
\(\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+...+\frac{2}{x\left(x+1\right)}=\frac{11}{40}\)VỚI X thuộc N*
