a) Ta có: \(x:3\dfrac{1}{15}=1\dfrac{1}{2}\)
\(\Leftrightarrow x:\dfrac{46}{15}=\dfrac{3}{2}\)
nên \(x=\dfrac{3}{2}\cdot\dfrac{46}{15}=\dfrac{23}{5}\)
b) Ta có: \(\left(1\dfrac{1}{5}-0.2\right)\cdot x=1\)
\(\Leftrightarrow\left(1+\dfrac{1}{5}-\dfrac{1}{5}\right)\cdot x=1\)
hay x=1
a, \(x:3\dfrac{1}{15}=1\dfrac{1}{12}\Leftrightarrow x:\dfrac{46}{15}=\dfrac{13}{12}\Leftrightarrow x=\dfrac{299}{90}\)
b, \(\left(1\dfrac{1}{5}-0,2\right)x=1\Leftrightarrow\left(\dfrac{6}{5}-\dfrac{1}{5}\right)x=1\Leftrightarrow x=1\)