Question

tìm x bt: (-6)^2x+2=1/36

Answer 1

\(\left(-6\right)^{2x+2}=\frac{1}{36}\)

=> \(\left(-6\right)^{2x+2}=\frac{1}{\left(-6\right)^2}\)

=> (-6)^{2x + 2} = (-6)^-2

=> 2x + 2 = -2

=> 2x = -4

=> x = -2

Vậy x = -2

Answer 2

\(\left(-6\right)^2x+2=\frac{1}{36}\)

\(\Rightarrow36x+2=\frac{1}{36}\)

\(\Rightarrow36x=\frac{1}{36}-2\)

\(\Rightarrow36x=-\frac{71}{36}\)

\(\Rightarrow x=\left(-\frac{71}{36}\right):36\)

\(\Rightarrow x=-\frac{71}{1296}\)

Vậy \(x=-\frac{71}{1296}.\)

Answer 3

\(\left(-6\right)^2x+2=\frac{1}{36}\Leftrightarrow36x+2=\frac{1}{36}\)

\(\Leftrightarrow36x=-\frac{71}{36}\Leftrightarrow x=-\frac{71}{1296}\)

Answer 4

\(\left(-6\right)^2x+2=\frac{1}{36}\)

\(36x+2=\frac{1}{36}\)

\(36x=\frac{1}{36}-2\)

\(36x=-\frac{71}{36}\)

\(x=-\frac{71}{36}:36\)

\(x=-\frac{71}{1296}\)

vậy \(x=-\frac{71}{1296}\)