\((x+1)(3-2x)=-2x(x-5)\)
\(<=>(x+1)(3-2x)-2x(x-5)=0\)
\(<=>3x-2x^2+3-2x-2x^2+10x=0\)
\(<=>11x-4x^2+3=0\)
\(<=>[11x=0<=>[x=0\)
\(<=>[-4x^2=0<=>[x=2\)
\(<=>[x+3=0<=>[x=-3\)
(x + 1)(3 - 2x) = -2x(x - 5)
3x - 2x² + 3 - 2x + 2x(x - 5)
-2x² + x + 3 + 2x² - 10x = 0
-9x = -3
x = 1/3