Question

Tìm x biết:
(x-3)^x+2-(x-3)^x+8=0

Answer 1

\(\left(x-3\right)^{x+2}-\left(x-3\right)^6.\left(x-3\right)^{x+2}=0\\ \left(x-3\right)^2\left[1-\left(x-3\right)^6\right]=0\\ \left[{}\begin{matrix}\left[1-\left(x-3\right)^6\right]=0\\\left(x-3\right)^{x+2}=0\end{matrix}\right.=>\left[{}\begin{matrix}1=x-3\\x-3=0\end{matrix}\right.=>x=4;x=3\)