\(\left|x-1\right|=3x+2\)
\(\Rightarrow\hept{\begin{cases}x-1=3x+2\\x-1=-\left(3x+2\right)\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x-3x=2+1\\x-1=-3x-2\end{cases}}\Rightarrow\hept{\begin{cases}-2x=3\\x+3x=-2+1\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=3:\left(-2\right)\\4x=-1\end{cases}}\Rightarrow\hept{\begin{cases}x=\frac{3}{-2}\\x=-\frac{1}{4}\end{cases}}\)
Vậy \(x\in\left\{\frac{3}{-2};-\frac{1}{4}\right\}\)
Ủng hộ mk nha !!! ^_^