\(Th1:x-2019>0\)
\(x-2019-x+2019=0\)
\(0x=0\)
Vậy \(|x-2019|-x+2019=0\)với tất cả giá trị x
\(th2:x-2019< 0\)
\(-x+2019-x+2019=0\)
\(\Rightarrow2x=4038\)
\(\Rightarrow x=2019\)
tìm x biết \(\left(3.\left|x.\left(-24\right)\right|.7^{2019}\right)=2.7^{2020}.\frac{1}{2020}\)
Tìm x, biết:
a) \(x-\left\{\left[-x-\left(x+3\right)\right]-\left[\left(x+2018\right)-\left(x+2019\right)\right]+21\right\}=2020\)
b) \(\frac{1}{x}-\left\{\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+...+\frac{1}{2018.2020}\right\}=\frac{1}{2019}\)
Help me! ( tặng 2 - 3 tk )
\(\left|x\right|+\left|x+1\right|=2019\)
\(\left|x\right|+\left|x+1\right|=0\)
Tìm x biết :
a} | x | + x = 0
b} | x | - x = 0
c} | x - 1 | + 2019 = 0
d} |2017| +|-2019| + |0| + |-2| - |2019|
MN ƠI GIÚP MÌNH CÒN ĐI HOK >W<
\(\left|x-3y\right|^{2019}+\left|y+4\right|^{2020}=0\)
Tìm x, y thỏa \(\left(2x-y+7\right)^{2018}+\left(\left|x-3\right|\right)^{2019}\le0\)
Tìm x biết
a) \(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2019}\right).x=\frac{2018}{1}+\frac{2017}{2}+\frac{2016}{3}+...+\frac{2}{2017}+\frac{1}{2018}\)
b) \(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{2017}{2019}\)
Câu 1: Tính giá trị biểu thức sau
A=\(\left(-1\right).\left(-1\right)^2.\left(-1\right)^3.\left(-1\right)^4...\left(-1\right)^{2018}.\left(-1\right)^{2019}\)
Câu 2: Tìm x, biết
\(\frac{x+1}{2}=\frac{8}{x+1}\)
tìm x biết \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x.\left(x+1\right)}=\frac{2019}{2020}\)
