\(\left(x-1\right)^2= \left(1-x\right)^3\)
Vì \(\left(x-1\right)^2=\left(1-x\right)^2\)
Suy ra: \(\left(1-x\right)^2=\left(1-x\right)^3\)
Ta thấy: \(1^2=1^3=1\); \(0^2=0^3=0\)
Suy ra 1-x=0 hoặc 1-x=1
=>x=1 hoặc x=0
Vậy ...........
Tìm x biết:
\(\left|x+1\right|+\left|x+2\right|+\left|x+3\right|+\left|x+4\right|=5x-1\)-1
\(\left|x+1,1\right|+\left|x+1,2\right|+\left|x+1,3\right|+\left|x+1,4\right|=5x\)
\(\left|x+1\right|-\left|3x+2\right|=x+2\)
Tìm x biết:
1) \(\left|x\right|=\left|x\left(x+2\right)\right|\)
2) \(\left|x-2\right|=\left|x\left(x+2\right)\right|\)
3) \(\left|x+1\right|=\left|x^2+4x+3\right|\)
Tìm x,y biết
\(\dfrac{6}{\left(x-1\right)^2+2}=\left|y-1\right|+\left|y-2\right|+\left|y-3\right|+1\)
1, Tìm x,y,z biết :
\(\left|x-6\right|+\left|x-10\right|+\left|x-2022\right|+\left|y-2014\right|+\left|z-2015\right|=2016\)
2, Tìm cặp số nguyên x,y biết :
\(\left|x-5\right|+\left|1-x\right|=\frac{12}{\left|y+1\right|+3}\)
Tìm x biết
1) \(\left(2x+3\right)\left(x-4\right)+\left(x-5\right)\left(x-2\right)=\left(3x-5\right)\left(x-4\right)\)
2)\(\left(8x-3\right)\left(3x+2\right)-\left(4x+7\right)\left(x+4\right)=\left(2x+1\right)\left(5x+1\right)-33\)
3)\(6x\left(3x+5\right)-2x\left(9x-2\right)+\left(17-x\right)\left(x-1\right)+x\left(x-18\right)-17x^2=0\)
4)\(\left(x-1\right)\left(x+2\right)-\left(x-3\right)+5x-7=0\)
Giúp mình nha. Camon nhiều
Tìm x biết :
1. \(\left|2x-1\right|=1-2x\)
2. \(\left|x-1\right|+\left|x-2\right|=1\)
3. \(\left|x+1\right|+\left|x+2\right|=3\)
4. \(\left|x+2\right|+\left|x+3\right|=4\left(x-1\right)-\left|x-1\right|\)
5. \(\left|x+2\right|+\left|x+3\right|=4\left(x+1\right)-\left|x-1\right|\)
Các bạn trình bày cách giải, đúng thì mik tick cho nhé
tìm x biết x ko thuoc {1;3;8;20} va
\(\frac{2}{\left(x-1\right).\left(x-3\right)}+\frac{3}{\left(x-3\right).\left(x-8\right)}+\frac{12}{\left(x-8\right).\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)
Tìm x biết:
\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=\frac{3}{4}\)
1. Tìm x ϵ Q sao cho:
a) (2x-3). (x+1) < 0.
b) \(\left(x-\frac{1}{2}\right).\left(x+3\right)>0\)
2.Tính:
S=\(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{999.1001}\)
3.Tìm x: Biết x không thuộc{-2; -5; -10; -17}
\(\frac{3}{\left(x+2\right).\left(x+5\right)}+\frac{5}{\left(x+5\right).\left(x+10\right)}+\frac{7}{\left(x+10\right).\left(x+17\right)}=\frac{x}{\left(x+2\right).\left(x+17\right)}\)
Tìm x biết: \(\left|x^2-3x\right|+\left|\left(x+1\right)\left(x-3\right)\right|=0\)
